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Math Help - Serious algebra problems...

  1. #1
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    Serious algebra problems...

    I am having a difficult problem solving a few algebra problems. I am not new to forums, but am new to this forum. Here is what I need help with.

    The first part is all raised to the 3/2.


    1.((16a^(-4)) ^3/2 * (4ab^(1/2))^-2
    ( b^8 )

    I got an answer with a denominator. 4
    a^8 b^13

    According to the rules, is this correct?

    2. 4y^(-2) -2x^(-1)
    (xy)^(-1)

    I am completely lost on this one. Not sure what to do after shifting the variables, to make them positive.


    All help will be appreciated.
    Last edited by russainred95; January 11th 2010 at 09:25 PM.
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  2. #2
    MHF Contributor Amer's Avatar
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    Quote Originally Posted by russainred95 View Post

    1.((16a^(-4)) ^3/2 * (4ab^(1/2))^-2
    ( b^8 )

    I got an answer with a denominator. 4
    a^8 b^13

    According to the rules, is this correct?

    2. 4y^(-2) -2x^(-1)
    (xy)^(-1)


    All help will be appreciated.
    1)\;\; \frac{(16a^{-4})^{\frac{3}{2}}(4ab^{\frac{1}{2}})^{-2}}{b^8}

    \frac{16^\frac{3}{2}}{b^8 \cdot (a^4)^{\frac{3}{2}} \cdot 4^2 \cdot a^2 \cdot b}

    \frac{4^3}{b^9 \cdot a^8\cdot 4^2} = \frac{4}{b^9 \cdot a^8}



    2)\;\; \frac{4y^{-2} - 2 x^{-1}}{(xy)^{-1}}

    \frac{4 y^{-2}}{(xy)^{-1}} - \frac{2x^{-1}}{(xy)^{-1}}

    \frac{4 (xy)}{y^2} - \frac{2(xy)}{x}

    \frac{4x}{y} - 2y

    \frac{4x-2y^2}{y}
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  3. #3
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    Thank you very much. Are you using some sort of tool to solve those problems?
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