Quadratic with complex roots

Hi there,

I'm looking for some confirmation that i have done this correctly/the easiest way,

Rgds.

Resolve $\displaystyle 9x^2-36x+37$ into factors.

= 9($\displaystyle x-\alpha$)($\displaystyle x-\beta$)

$\displaystyle \frac{36+or-\sqrt{36^2-4*9*37}}{18}$

$\displaystyle \frac{36+or-\sqrt{-36}}{18}$

$\displaystyle \frac{36+or-j6}{18}$

$\displaystyle 2+or-j\frac{1}{3}$

$\displaystyle 9(x-2+j\frac{1}{3})(x-2-j\frac{1}{3})$

$\displaystyle 3(x-2+j\frac{1}{3})3(x-2-j\frac{1}{3})$

$\displaystyle (3x-6+j)(3x-6-j)$