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Math Help - More Simplification of Logs!

  1. #1
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    Smile More Simplification of Logs!

    Hi there, I was wondering if anyone could check my answer to this past examination question.

    Thanks in advance

    Express the following without logarithms:

    logX=logP+2logQ-logK-3

    I got an answer of x={[(P+Q^2)/K]10^3}

    Thanks again for any help

    Mike
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  2. #2
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by mikewhant View Post
    Hi there, I was wondering if anyone could check my answer to this past examination question.

    Thanks in advance

    Express the following without logarithms:

    logX=logP+2logQ-logK-3

    I got an answer of x={[(P+Q^2)/K]10^3}

    Thanks again for any help

    Mike
    I don't see an exponent?

    log(x) = logP + logQ^2 - logK - log10^3 = log \left(\frac{PQ^2}{10^3K}\right)
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  3. #3
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    Quote Originally Posted by e^(i*pi) View Post
    I don't see an exponent?

    log(x) =  log \left(\frac{PQ^2}{10^3K}\right)
    would it matter what the base was? As long as they were all the same then

    x = \frac{PQ^2}{10^3K}
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  4. #4
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by pickslides View Post
    would it matter what the base was? As long as they were all the same then

    x = \frac{PQ^2}{10^3K}
    As I've answered it, it would matter because of that -3 on the end. If it was base b

    x = \frac{PQ^2}{b^3K}

    Of course the OP may have meant (K-3) in which case it wouldn't matter
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