# More Simplification of Logs!

• Jan 9th 2010, 10:59 AM
mikewhant
More Simplification of Logs!
Hi there, I was wondering if anyone could check my answer to this past examination question.

Express the following without logarithms:

logX=logP+2logQ-logK-3

I got an answer of x={[(P+Q^2)/K]10^3}

Thanks again for any help

Mike
• Jan 9th 2010, 11:07 AM
e^(i*pi)
Quote:

Originally Posted by mikewhant
Hi there, I was wondering if anyone could check my answer to this past examination question.

Express the following without logarithms:

logX=logP+2logQ-logK-3

I got an answer of x={[(P+Q^2)/K]10^3}

Thanks again for any help

Mike

I don't see an exponent?

$log(x) = logP + logQ^2 - logK - log10^3 = log \left(\frac{PQ^2}{10^3K}\right)$
• Jan 9th 2010, 11:33 AM
pickslides
Quote:

Originally Posted by e^(i*pi)
I don't see an exponent?

$log(x) = log \left(\frac{PQ^2}{10^3K}\right)$

would it matter what the base was? As long as they were all the same then

$x = \frac{PQ^2}{10^3K}$
• Jan 9th 2010, 11:40 AM
e^(i*pi)
Quote:

Originally Posted by pickslides
would it matter what the base was? As long as they were all the same then

$x = \frac{PQ^2}{10^3K}$

As I've answered it, it would matter because of that -3 on the end. If it was base b

$x = \frac{PQ^2}{b^3K}$

Of course the OP may have meant (K-3) in which case it wouldn't matter