logb(a)+logc(b)+loga(c)=1/loga(b) + logb(c) + 1/logc(a)
Hrmm.. im thinking loga(a)/loga(b), how does that equal to logb(a) ?
Hello smmmcThe log of a number, to a certain base, is that power to which the base must be raised to get the number.So, by definition, if
thenTherefore, using the laws of indices:and so, using the definition of a log once again:Grandad
OK. I see that you get it to here:I understand the difficulty you're having with logs, because the definition of a logarithm is a bit 'inside-out' somehow. But it's important for you to get your head around it, so here's a bit more explanation....so from logb(a)=1/x, i just see this as b^(1/2)=a
If , then is the power to which must be raised in order to give the answer . Right?
So, looking back to the definition of a log that I gave you at the beginning, this means that .
Well if and , then, by substitution, .