# f * g * h

• Jan 8th 2010, 04:03 PM
l flipboi l
f * g * h
Hello,

Can you please verify that I did the correct operation?
\$\displaystyle
f(x) = 2x-1\$
\$\displaystyle g(x) = x^2\$
\$\displaystyle h(x) = 1 - x\$

\$\displaystyle 2(1-x)^2 -1\$
\$\displaystyle 2(1-x^2)-1\$
\$\displaystyle 2-2x^2-1\$
\$\displaystyle -2x^2-1\$

Thanks!
• Jan 8th 2010, 04:09 PM
l flipboi l
Quote:

Originally Posted by l flipboi l
Hello,

Can you please verify that I did the correct operation?
\$\displaystyle
f(x) = 2x-1\$
\$\displaystyle g(x) = x^2\$
\$\displaystyle h(x) = 1 - x\$

\$\displaystyle 2(1-x)^2 -1\$
\$\displaystyle 2(1-x^2)-1\$
\$\displaystyle 2-2x^2-1\$
\$\displaystyle -2x^2-1\$

Thanks!

\$\displaystyle 2x^2-4x+1\$
• Jan 8th 2010, 04:32 PM
Sudharaka
Dear l flipboi l,

I think intead of \$\displaystyle {2(1-x^2)-1}\mbox{ it should be }{2(1-2x+x^2)-1}\$
• Jan 8th 2010, 04:50 PM
l flipboi l
Quote:

Originally Posted by Sudharaka
Dear l flipboi l,

I think intead of \$\displaystyle {2(1-x^2)-1}\mbox{ it should be }{2(1-2x+x^2)-1}\$

Sudharaka,

actually, you're right...you just expanded (1-x^2).
• Jan 8th 2010, 05:06 PM