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Math Help - Squares and routes

  1. #1
    Senior Member Mukilab's Avatar
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    Squares and routes

    If I want to cancel a square a.k.a 4^2 do I multiply or add it to the square route of said number (4 here)
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  2. #2
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    Quote Originally Posted by Mukilab View Post
    If I want to cancel a square a.k.a 4^2 do I multiply or add it to the square route of said number (4 here)
    This small isolated part of what is clearly a larger question makes no sense without more context.
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  3. #3
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    You don't add or multiply the square root, you 'take' the square root.

    I.e you may have x^2 = 81 and you want to find x

    which is the same as

    x^2 = 9^2

    now you can see you can take the square root of both sides.

    \sqrt{x^2} = \sqrt{9^2}

    which in turns yields

    x = 9

    As square and square root are opposites.

    Now go ahead and change the world!
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  4. #4
    Senior Member Mukilab's Avatar
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    Quote Originally Posted by mr fantastic View Post
    This small isolated part of what is clearly a larger question makes no sense without more context.
    No, I just need to know this for a simultaneous equation. If I need to cancel out a 4^2 do I use multiply by \sqrt{4} or add by \sqrt{4}
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  5. #5
    Master Of Puppets
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    I am starting to agree with this comment

    Quote Originally Posted by mr fantastic View Post
    This small isolated part of what is clearly a larger question makes no sense without more context.
    You have confused me friend, please post the full question, I can't read your mind!
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  6. #6
    Senior Member Mukilab's Avatar
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    Quote Originally Posted by pickslides View Post
    I am starting to agree with this comment



    You have confused me friend, please post the full question, I can't read your mind!
    ....

    By eliminating y find solutions to the simultaneous equations

    x^2+y^2=25
    y=2x-2
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  7. #7
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    Quote Originally Posted by Mukilab View Post
    ....

    By eliminating y find solutions to the simultaneous equations

    x^2+y^2=25
    y=2x-2
    Substitute y=2x-2 into x^2+y^2=25, expand, simplify and solve the quadratic for x. Then substitute the values of x into y=2x-2 to get y.
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