# Thread: Mean time and varying inversely

1. ## Mean time and varying inversely

The mean playing time of these was 42mins

She sold 5
The mean playing time of the 25 left is now 42.8
Calculate the mean playing time of the 5 CDs that Amy sold.

2)She shutter speed S of a camera varies inversely as the square of the aperture setting, F. When F=8, S=125. Is this the same as the proportional formula where F=KS?

2. Originally Posted by Mukilab

The mean playing time of these was 42mins

She sold 5
The mean playing time of the 25 left is now 42.8
Calculate the mean playing time of the 5 CDs that Amy sold.

2)She shutter speed S of a camera varies inversely as the square of the aperture setting, F. When F=8, S=125. Is this the same as the proportional formula where F=KS?
1) Let $a = \frac{t_1 + t_2 + .... + t_{25}}{30}$ and $b = \frac{t_{26} + .... + t_{30}}{30}$. Then:

$42 = \frac{a + b}{30}$ .... (1)

$42.8 = \frac{a}{25}$ .... (2)

Solve equations (1) and (2) simultaneously to calculate the value of $\frac{b}{30}$.

2) No. $S = \frac{k}{F^2}$.

3. Originally Posted by mr fantastic
1) Let $a = \frac{t_1 + t_2 + .... + t_{25}}{30}$ and $b = \frac{t_{26} + .... + t_{30}}{30}$. Then:

$42 = \frac{a + b}{30}$ .... (1)

$42.8 = \frac{a}{25}$ .... (2)
Since you defined a with a denominator of 30, shouldn't this be
$42.8= \frac{a}{25}(30)$? Otherwise you are going to get a negative number for b.

Solve equations (1) and (2) simultaneously to calculate the value of $\frac{b}{30}$.

2) No. $S = \frac{k}{F^2}$.

4. Originally Posted by HallsofIvy
Since you defined a with a denominator of 30, shouldn't this be
$42.8= \frac{a}{25}(30)$? Otherwise you are going to get a negative number for b.

I found that and assumed it was right :/

5. Originally Posted by HallsofIvy
Since you defined a with a denominator of 30, shouldn't this be
$42.8= \frac{a}{25}(30)$? Otherwise you are going to get a negative number for b.
Thankyou. Yes, a slip-up on my part.