Suppose varies directly as the cube of . If when , what is if is 10?
Please help me I'm stuck on this and I have an online based test that is due pretty soon.
Hi grud315,
If p varies directly as the cube of q, then we have:
$\displaystyle p=kq^3$
Substitute your values p = 7 and q = 11 and solve for k.
$\displaystyle 7=k(11)^3$
k is your constant of variation.
Use this value of k, along with q = 10 to solve for p.
$\displaystyle p=k(10)^3$