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Math Help - Halfway through equation

  1. #1
    Senior Member Mukilab's Avatar
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    Halfway through equation

    I need h in terms of x

    Got up to

    \frac{4}{3} \cdot 2x=\frac{1}{3} \cdot h


    WIP please with answer.
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  2. #2
    Senior Member Dinkydoe's Avatar
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    Multiply both sides with 3 to obtain:  8x = h

    That is what you want right?
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  3. #3
    Senior Member Mukilab's Avatar
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    Oh god. I came up with \frac{\frac{4}{3} 2x}{\frac{1}{3}}


    Thanks though, I'm so forgetful ^^
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  4. #4
    Senior Member Dinkydoe's Avatar
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    Oh god. I came up with
    That is correct: \frac{\frac{4}{3}2x}{\frac{1}{3}} = \frac{4\times \frac{1}{3}\times 2x}{\frac{1}{3}}= 8x
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  5. #5
    Senior Member Mukilab's Avatar
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    yes but it's probably not what the examiner wanted! XD
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  6. #6
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    Dividing by \frac{1}{3} is multiplying by 3.

    For example....

    Try dividing 12 into 3 equal parts, \frac{12}{3}=4

    Now try dividing 12 into \frac{1}{3} parts...

    Make sense?
    thought not...

    What is 12 divided by \frac{1}{3} ?

    \frac{12}{\frac{1}{3}}=\frac{(36)\frac{1}{3}}{\fra  c{1}{3}}=36\frac{\frac{1}{3}}{\frac{1}{3}}

    Expressing the numerator as a multiple of the denominator allows cancellation
    of non-zero common factors (after all, a third is 0.67ish).

    Any number divided by itself is 1, except zero.
    A fraction divided by itself is 1
    So, 12 divided by a third is 36, because it's really 12 times 3.

    Dividing by a fraction is multiplying by the fraction turned upside down.

    of course, this means... multiply by the numerator and divide by the denominator.
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  7. #7
    Senior Member Mukilab's Avatar
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    Amazing. I really do love your ways of explaining things. Please do continue to help me in further issues if you find time
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  8. #8
    MHF Contributor
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    Thanks, Mukilab,

    you're welcome.

    The vectors question you had a few days ago......

    The critical thing to understand there was \overrightarrow{xy}=\overrightarrow{y}-\overrightarrow{x}

    The vector \overrightarrow{xy} starts at the point x and ends at y.

    The vectors \overrightarrow{x} and \overrightarrow{y} both start at the origin.

    You understand this by examining the parallelograms.
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