I need h in terms of x
Got up to
$\displaystyle \frac{4}{3} \cdot 2x=\frac{1}{3} \cdot h$
WIP please with answer.
Dividing by $\displaystyle \frac{1}{3}$ is multiplying by $\displaystyle 3.$
For example....
Try dividing 12 into 3 equal parts, $\displaystyle \frac{12}{3}=4$
Now try dividing 12 into $\displaystyle \frac{1}{3}$ parts...
Make sense?
thought not...
What is 12 divided by $\displaystyle \frac{1}{3}$ ?
$\displaystyle \frac{12}{\frac{1}{3}}=\frac{(36)\frac{1}{3}}{\fra c{1}{3}}=36\frac{\frac{1}{3}}{\frac{1}{3}}$
Expressing the numerator as a multiple of the denominator allows cancellation
of non-zero common factors (after all, a third is 0.67ish).
Any number divided by itself is 1, except zero.
A fraction divided by itself is 1
So, 12 divided by a third is 36, because it's really 12 times 3.
Dividing by a fraction is multiplying by the fraction turned upside down.
of course, this means... multiply by the numerator and divide by the denominator.
Thanks, Mukilab,
you're welcome.
The vectors question you had a few days ago......
The critical thing to understand there was $\displaystyle \overrightarrow{xy}=\overrightarrow{y}-\overrightarrow{x}$
The vector $\displaystyle \overrightarrow{xy}$ starts at the point x and ends at y.
The vectors $\displaystyle \overrightarrow{x}$ and $\displaystyle \overrightarrow{y}$ both start at the origin.
You understand this by examining the parallelograms.