if i understand the questions correctly:
which means this equation is true for every x...
and the second one is similar:
which also means this equation is true for every x, except x=0,
when is not defined.
Working on this set of questions, and Ive come to two difficult qns, which Im not sure which route I should take at tackling them, its come to a point where Ive written and erased it so many times.. my page has ripped *pressure*
Any help would be greatly appreciated.
Solve for x:
1.
x/m + n = x/n + m
2.
(1/ x + a) + (1 / x + 2a) = 2 /x + 3a
Thank you.
I hope your question is
[1/(x+a)]+[1/(x+2a)]=2/(x+3a)
this is equal to
(x+a+x+2a)/[(x+a)(x+2a)]= 2/(x+3a)
=(2x+3a)/[(x+a)(x+2a)]= 2/(x+3a)
now cross multiply and we get
2x^2+9ax+9a^2=2x^2+6ax+4a^2
or
3ax=-5a^2
finally
x=-5a/3
2) or on the second thought if your question is
[(1/x)+a]+[(1/x)+2a]=[(2/x)+3a]
then it is an identity. x can have any value except 0