$\displaystyle a^2-9b^2$ Don't know what to put as the subject...-1/1?
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Originally Posted by Mukilab $\displaystyle a^2-9b^2$ $\displaystyle a^2-9b^2$ $\displaystyle a^2-3^2b^2$ $\displaystyle a^2-(3b)^2$ using the difference of 2 squares rule $\displaystyle (a-3b)(a+3b)$ Originally Posted by Mukilab Don't know what to put as the subject...-1/1? what do you mean by this?
Originally Posted by pickslides $\displaystyle a^2-9b^2$ $\displaystyle a^2-3^2b^2$ $\displaystyle a^2-(3b)^2$ using the difference of 2 squares rule $\displaystyle (a-3b)(a+3b)$ what do you mean by this? I meant what should I put at the start of the quadratic, take the 'subject' as x. You would do (x ......)(x......) Thanks for the great explanation and WIP! ^^
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