Make r the subject

$\displaystyle P=\pi r+2r+2a$

I could only get

$\displaystyle \frac{P-2a}{\pi}=r+\frac{2r}{\pi}$

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- Jan 6th 2010, 11:40 AMMukilabSubject of the formula
Make r the subject

$\displaystyle P=\pi r+2r+2a$

I could only get

$\displaystyle \frac{P-2a}{\pi}=r+\frac{2r}{\pi}$ - Jan 6th 2010, 11:44 AMe^(i*pi)
- Jan 6th 2010, 11:50 AMMukilab
- Jan 6th 2010, 11:51 AMe^(i*pi)
- Jan 6th 2010, 11:53 AMMukilab