1. ## inequality question :)

solve the inequality..

-35 < 6x + 7 < 1

2. Originally Posted by johnsmith666
solve the inequality..

-35 < 6x + 7 < 1
First solve $-35 < 6x + 7$ then solve $6x + 7 < 1$

$-35 = 6x + 7$
$-42 = 6x$
$-7 = x$

so everything between -7 (-7 not included) and infinity is a possible answer

$6x + 7 = 1$
$6x = -6$
$x = -1$

so everything between -1 and - infinity is a possible answer here

making the final answer between -7 and -1 (both not included)... (I totally forgot how to put this mathematically )

Edit: something like this... [-7,-1](I think? )

3. solve the inequality..

$-35 < 6x + 7 < 1$

isolate the varible in the middle

$-42 < 6x< -6$

divide each term by 6

$-7 < x < -1$

the solution set is $[-7,-1]$

4. thanksss shinnnndingggg

5. Originally Posted by bigwave
isolate the varible in the middle

$-42 < 6x< -6$

divide each term by 6

$-7 < x < -1$
Lol, I got owned...

But this won't always work, will it?

edit: Use the thanks button :'D

6. u waatttt?? im confusedd i used both ur answers cos i needed to show working. im doing an AS level paper u see.

7. if we try to divide each term by a variable it won't work because we do not know the sign.

i followed an example out of text book which was a similiar problem

we both have the same answers

consider multiple replies to the same post a good thing...

8. could u try and do another question for me please .

express x^2 - 5x +1/4 in the form (x-a)^2 - b

thanks

9. This AS level is harder then the GCSE papers I've seen...

10. Originally Posted by johnsmith666
could u try and do another question for me please .

express x^2 - 5x +1/4 in the form (x-a)^2 - b

thanks
do you know how to "complete the square" on this..