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Math Help - (4x-2)/2 * 3x/4 = ?? (Fractions)

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    (4x-2)/2 * 3x/4 = ?? (Fractions)

    I asked on Yahoo! Answers, but they didn't explain it very well.
    Can someone please tell me how to get the answer? The more details the better.

    (4x-2)/2 * 3x/4 = ?
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  2. #2
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    Quote Originally Posted by GrindingxxTeeth View Post
    I asked on Yahoo! Answers, but they didn't explain it very well.
    Can someone please tell me how to get the answer? The more details the better.

    (4x-2)/2 * 3x/4 = ?

    \frac{4x-2}{2} \times \frac{3x}{4} = \frac{(4x-2)\times 3x}{2\times 4} = \frac{12x^2-6x}{8}

    Now simplify
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    Thank you for responding, but how do you get that answer? What do you multiply or add?
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    Quote Originally Posted by GrindingxxTeeth View Post
    Thank you for responding, but how do you get that answer? What do you multiply or add?

    I multiplied as your question suggested.
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  5. #5
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    But 4x - 2 is 2x. 2x multiplied by 3 is 6x, so where does the 12x2 come from?
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    Quote Originally Posted by GrindingxxTeeth View Post
    But 4x - 2 is 2x.

    No it's not, 4x and -2 are not like terms.
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    ... So then can you show me the steps you used to get that answer?
    Sorry if I seem thick here, but I am sooo lost on this problem I don't even know where to begin.
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  8. #8
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    Quote Originally Posted by GrindingxxTeeth View Post
    But 4x - 2 is 2x. 2x multiplied by 3 is 6x, so where does the 12x2 come from?
    ( 4x-2)(3x)

    we are distributing the 3x to the terms inside (4x - 2)so we have (4x(3x)- 2(3x)) which is 12x^2 - 6x
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  9. #9
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    Quote Originally Posted by GrindingxxTeeth View Post
    ... So then can you show me the steps you used to get that answer?
    Sorry if I seem thick here, but I am sooo lost on this problem I don't even know where to begin.
    Begin by going back and reviewing the basic algebra that this question depends on. Attempt easier questions as a lead-in to this question. If you do not understand the basic things there is no point trying to understand how they are applied to questions like this one. Your real problem is not this question, it is the underpinning algebra.

    By the way, a solution may not seem to be explained very well if you are given guidance on how to solve the question but you do not understand the basic algebra underpinning that guidance.
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  10. #10
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    ...
    And now I'm off to try math forum #2 since apparently you guys don't like helping people. Why not just show the steps? Is it really that hard?
    Whatever. Hopefully a different forum will be more helpful.
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  11. #11
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    Quote Originally Posted by GrindingxxTeeth View Post
    ...
    And now I'm off to try math forum #2 since apparently you guys don't like helping people. Why not just show the steps? Is it really that hard?
    Whatever. Hopefully a different forum will be more helpful.
    What we don't like is people who insist on being given a complete solution that shows every single step.

    Despite what you might think, it is not helpful to give you an entire solution. Post #2 gave you everything except the last step but you did not understand it. I have said the reasons why.

    Do yourself a favor and review the basic material so that you can understand the help that people are trying to give you.

    Thread closed.
    Last edited by mr fantastic; January 4th 2010 at 02:48 PM.
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  12. #12
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    Quote Originally Posted by GrindingxxTeeth View Post
    ...
    And now I'm off to try math forum #2 since apparently you guys don't like helping people. Why not just show the steps? Is it really that hard?
    Whatever. Hopefully a different forum will be more helpful.
    Bye. Definitely will miss you...
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