Factorise $\displaystyle m^2+9m+20$ I thought it would be $\displaystyle (m+10)(m-1) $ but that wouldn't work
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Originally Posted by Mukilab Factorise $\displaystyle m^2+9m+20$ I thought it would be $\displaystyle (m+10)(m-1) $ but that wouldn't work Both your signs will be + since 9 and 20 are both greater than 0. Think about what other numbers multiply to make 20. $\displaystyle 20 = 1 \times 20 \: , 2 \times 10 , 4 \times 5$ From the above pick a pair that add up to 9 The answer is $\displaystyle (m+4)(m+5)$
$\displaystyle m^2+9m+20=(m+5)(m+4)$
Lol I am such an idiot >.<
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