Yes or no?
1. Cancel the common factor.
2. Determine the domain of the term at the LHS.
3. Set the numerator equal to zero, solve for x.
By the way: The simplification isn't necessary here: Multiply both sides of the equation by the denominator after you've determined the domain of the complete term.
The denominator can never equal 0
Values inside logarithms must be greater than 0
Values inside even roots (such as square root) must be greater than 0
In your case which means any value that makes is not part of the domain
So... it's safe to assume the following; , ; ?
then how does this work out?
Originally Posted by earboth
does this not grant two answers for ?
Edit: O wait, I think I got it now. The domain also includes which in the end means you do have to factorise both nominator and denominator of the original equation.