# Thread: multiplying out and then integrating the following expression

1. ## multiplying out and then integrating the following expression

Hello
Im and struggling to integrate the following

sqrt(x^2+3)

Initially how would I multiply it out? is it a case of just taking each term to the half power?

x^2 becomes just x and 3 becomes 3^1/2 ?

Then to integrat does it become 1/2x^2 + 2^3/2 + c

Thanks

2. I'm an idiot, see Mr. F's reply below

3. Originally Posted by 200001
Hello
Im and struggling to integrate the following

sqrt(x^2+3)

Initially how would I multiply it out? is it a case of just taking each term to the half power?

x^2 becomes just x and 3 becomes 3^1/2 ?

Then to integrat does it become 1/2x^2 + 2^3/2 + c

Thanks
If x = 1 are you claiming that $\sqrt{1 + 3} = 1 + \sqrt{3}$ !!??

You are completely wrong. $\sqrt{x^2 + 3} \neq x + \sqrt{3}$.

To do this integral requires a trigonometric substitution. See integrate Sqrt[x^2 + 3] - Wolfram|Alpha (be sure to click on Show steps).

4. Hi
Thanks for the link.
I must say though I feel a little put off by your "You are completely wrong" approach.
I am a young man trying my best at math that is a few years beyond my peers and think a little more support would be nice. I feel the tone is very dismissive especially from someone connected to the site.

Thanks once again for the direction though