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Math Help - multiplying out and then integrating the following expression

  1. #1
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    multiplying out and then integrating the following expression

    Hello
    Im and struggling to integrate the following

    sqrt(x^2+3)

    Initially how would I multiply it out? is it a case of just taking each term to the half power?

    x^2 becomes just x and 3 becomes 3^1/2 ?

    Then to integrat does it become 1/2x^2 + 2^3/2 + c

    Thanks
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  2. #2
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    e^(i*pi)'s Avatar
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    I'm an idiot, see Mr. F's reply below
    Last edited by e^(i*pi); January 3rd 2010 at 04:29 AM.
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  3. #3
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    Quote Originally Posted by 200001 View Post
    Hello
    Im and struggling to integrate the following

    sqrt(x^2+3)

    Initially how would I multiply it out? is it a case of just taking each term to the half power?

    x^2 becomes just x and 3 becomes 3^1/2 ?

    Then to integrat does it become 1/2x^2 + 2^3/2 + c

    Thanks
    If x = 1 are you claiming that \sqrt{1 + 3} = 1 + \sqrt{3} !!??

    You are completely wrong. \sqrt{x^2 + 3} \neq x + \sqrt{3}.

    To do this integral requires a trigonometric substitution. See integrate Sqrt[x^2 + 3] - Wolfram|Alpha (be sure to click on Show steps).
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  4. #4
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    Hi
    Thanks for the link.
    I must say though I feel a little put off by your "You are completely wrong" approach.
    I am a young man trying my best at math that is a few years beyond my peers and think a little more support would be nice. I feel the tone is very dismissive especially from someone connected to the site.

    Thanks once again for the direction though
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