Thread: My computations here, is there an easier way?

I'm just a student of basic math.

I think that my computations are correct with this math problem. There was probably a better way to reach the answer, but I wouldn't know it. Anyone?

365days,
5hr, 48 mins, 45.9747 secs
to make 6 hrs.
14sec more to make a min or make 49 min.
11min + 14sec to make 6hrs x 4= 24 hrs
So,365.208333 is 5hrs on 24hr day.

1440 min in a 24hr day.

300 min = 5hrs
plus 48 min. = 348 mins
plus 45.9747secs. of 60secs. is 76.6245%
348.766845 mins = 5 hrs, 48 mins, 45.9747 secs of 1 day

1440 min is a 24hr day.
348.766845 mins is what percentage of 24hrs or 1 day

Equels: 365.24219919791666665 days in one year?

Originally Posted by PughBear

I'm just a student of basic math.

I think that my computations are correct with this math problem. There was probably a better way to reach the answer, but I wouldn't know it. Anyone?

365days,
5hr, 48 mins, 45.9747 secs
to make 6 hrs.
14sec more to make a min or make 49 min.
11min + 14sec to make 6hrs x 4= 24 hrs
So,365.208333 is 5hrs on 24hr day.

1440 min in a 24hr day.

300 min = 5hrs
plus 48 min. = 348 mins
plus 45.9747secs. of 60secs. is 76.6245%
348.766845 mins = 5 hrs, 48 mins, 45.9747 secs of 1 day

1440 min is a 24hr day.
348.766845 mins is what percentage of 24hrs or 1 day

Equels: 365.24219919791666665 days in one year?

What are these strange ramblings? You have not once mentioned what you are trying to calculate. I can only guess you want to know how many days there are in any given year?

I just say there are days in a normal year and in a leap year. For long term calculations in which years are the unit of measure you can use which will include your leap years.

Solar Science says that there is exactly:
365days,
5hr, 48 mins, 45.9747 secs in a full solar year.

I know about leap-year taking up the slack sort to speak, in our calender year, I just figure this partial day to .24219919791666665 (decimal terms) from the 'extra time' per year, above. Understand, I didn't have a formula to work with, but by the numbers, or this 'rambling', as you say, before you.

Originally Posted by PughBear

I'm just a student of basic math.

I think that my computations are correct with this math problem. There was probably a better way to reach the answer, but I wouldn't know it. Anyone?

365days,
5hr, 48 mins, 45.9747 secs
to make 6 hrs.
14sec more to make a min or make 49 min.
11min + 14sec to make 6hrs x 4= 24 hrs
So,365.208333 is 5hrs on 24hr day.

1440 min in a 24hr day.

300 min = 5hrs
plus 48 min. = 348 mins
plus 45.9747secs. of 60secs. is 76.6245%
348.766845 mins = 5 hrs, 48 mins, 45.9747 secs of 1 day
348.766245 mins = 5 hrs, 48 mins, 45.9747 secs of 1 day

1440 min is a 24hr day.
348.766845 mins is what percentage of 24hrs or 1 day

Equels:
365.24219919791666665 days in one year?
365.242198781 days in one year

365days, 5hr, 48 mins, 45.9747 secs

365 + ( 5 + (48 + 45.9747/60 )/60)/24 = 365.242198781
Tropical Year 365.24219878 days

I do not understand exactly what you are asking.

If you are going to do any work involving time, it is best to use Universal Time as your reference.

Originally Posted by PughBear

Solar Science says that there is exactly:
365days,
5hr, 48 mins, 45.9747 secs in a full solar year.

I know about leap-year taking up the slack sort to speak, in our calender year, I just figure this partial day to .24219919791666665 (decimal terms) from the 'extra time' per year, above. Understand, I didn't have a formula to work with, but by the numbers, or this 'rambling', as you say, before you.

The 'rambling' had nothing to do with the numbers but with the fact that you did not, and still have not, said what you are trying to do!

Originally Posted by aidan

365days, 5hr, 48 mins, 45.9747 secs

365 + ( 5 + (48 + 45.9747/60 )/60)/24 = 365.242198781
Tropical Year 365.24219878 days

I do not understand exactly what you are asking.

If you are going to do any work involving time, it is best to use Universal Time as your reference.

Thank you for pointing out my error with the 348.766'2'45 instead of the miss-read 348.766'8'45 thus dividing '/' that number by 1440 mins. (in 1 day) brings me to .242198781'25', showing me that my calculator shows more digits than yours, lol.

However, your "time" formula doesn't cut it as shown:

"365 + ( 5 + (48 + 45.9747/60 )/60)/24"

48 + 45.9747 = 93.9747 / (divided) by 60 = 1.566245, showing (48 + 45.9747/60) part of the formula,

+ 5 = 6.566245 / by 60 = 0.10943741666666666666666666666667, showing (5+(48 + 45.9747/60 )/60) part of the formula,

/24 = .004559898923611111111111111111111111, showing ( 5 + (48 + 45.9747/60 )/60)/24 part of the formula,

+ 365 = 365.004559898923611111111111111111111111, showing what the entire formula equals.

All that I was trying to do is get a universal formula, which obvious, I'm being messed with about, that you plug in the hrs., mins., and secs (with decimal numbers) of one 24 hr. day and get the break down in numerics, whether I'm using the 'Tropical Time' or not. Now this may be easy for some of you, but it is not for me, OK? I hope that this clarifies things. Thank You!

Originally Posted by PughBear

Thank you for pointing out my error with the 348.766'2'45 instead of the miss-read 348.766'8'45 thus dividing '/' that number by 1440 mins. (in 1 day) brings me to .242198781'25', showing me that my calculator shows more digits than yours, lol.

However, your "time" formula doesn't cut it as shown:

"365 + ( 5 + (48 + 45.9747/60 )/60)/24"

48 + 45.9747 = 93.9747 / (divided) by 60 = 1.566245, showing (48 + 45.9747/60) part of the formula,

+ 5 = 6.566245 / by 60 = 0.10943741666666666666666666666667, showing (5+(48 + 45.9747/60 )/60) part of the formula,

/24 = .004559898923611111111111111111111111, showing ( 5 + (48 + 45.9747/60 )/60)/24 part of the formula,

+ 365 = 365.004559898923611111111111111111111111, showing what the entire formula equals.

All that I was trying to do is get a universal formula, which obvious, I'm being messed with about, that you plug in the hrs., mins., and secs (with decimal numbers) of one 24 hr. day and get the break down in numerics, whether I'm using the 'Tropical Time' or not. Now this may be easy for some of you, but it is not for me, OK? I hope that this clarifies things. Thank You!

When you say "math is hard", it is only hard because you are not following thorough with your swing.
I'm not preaching here, but you really really really need to know some basic fundamental rules of math before you proceed.
Division takes precedence over addition.
That means (simply) that you must do the division BEFORE you attempt the addition.

Look at the post and then look at your interpretation of it.
48 + 45.9747/60 = 48 + 0.7662456 = 48.766245

If you play sports, or even watch sports, you have heard the term "foul".
What you have done with the your math above is considered a "foul".

Just take a little more time, when "doing the math"

.

Originally Posted by aidan

365days, 5hr, 48 mins, 45.9747 secs

365 + ( 5 + (48 + 45.9747/60 )/60)/24 = 365.242198781
Tropical Year 365.24219878 days

I do not understand exactly what you are asking.

If you are going to do any work involving time, it is best to use Universal Time as your reference.

OK, learning that "Universal Time" is ambiguous (Universal Time - Wikipedia, the free encyclopedia) and someone mathematically figured out, from what I read, that about every 25,000 years the Earth cycles in our universe back to a beginning time position, how does all this fit in with "Sundial" measurements? or our real at home, sun to earth position, mathematically? Has anyone ever figured the math on this? Because to me, time isn't based on Sundial measurements anymore.

I've also read about a Christian Scientist from NASA who figured out the time/math of the missing day, that it really did happen, when 'the day' stood still back in Biblical times. I'm just wonder if "Universal Time" shouldn't be based on his computations, permanently. Because, again, to me, it would make keeping track of time much easier than relying on a continually changing/expanding universe that is being discovered and found everyday.

Time, we are here but a moment, then we are gone.

Thank you! and will do.

Originally Posted by aidan

When you say "math is hard", it is only hard because you are not following thorough with your swing.
I'm not preaching here, but you really really really need to know some basic fundamental rules of math before you proceed.
Division takes precedence over addition.
That means (simply) that you must do the division BEFORE you attempt the addition.

Look at the post and then look at your interpretation of it.
48 + 45.9747/60 = 48 + 0.7662456 = 48.766245

If you play sports, or even watch sports, you have heard the term "foul".
What you have done with the your math above is considered a "foul".

Just take a little more time, when "doing the math"

.

Another question please.
So the proper formula that I looking for would look like this. . . or should the x, y, z have different time
references assigned to them?

x= hours; y = minutes; z = seconds

365 + (x + (y + (z /60)/60)/24

Originally Posted by aidan

When you say "math is hard", it is only hard because you are not following thorough with your swing.
I'm not preaching here, but you really really really need to know some basic fundamental rules of math before you proceed.
Division takes precedence over addition.
That means (simply) that you must do the division BEFORE you attempt the addition.

Look at the post and then look at your interpretation of it.
48 + 45.9747/60 = 48 + 0.7662456 = 48.766245

If you play sports, or even watch sports, you have heard the term "foul".
What you have done with the your math above is considered a "foul".

Just take a little more time, when "doing the math"

.

How can I put this more simply?

What would you like to find out using this calculation?!

Just an equation like aidan had mention, or better formula, to get what I was looking for in an easier way than I first tried to do...off-the-cuff, with my bad math. OK?!

Originally Posted by e^(i*pi)

How can I put this more simply?

What would you like to find out using this calculation?!