Non-Basic solutions to equations...

**ZTM1989** · January 1st 2010, 07:25 AM

How would I go about calculating a non-basic solution to something like

2w + 3z = 6
2x + 3z = 8
y + 3z = 7

I'm guessing my solution is going to be a general solution with a free parameter?

**Soroban** · January 1st 2010, 07:54 AM

Hello, ZTM1989!

How would I go about calculating a non-basic solution to something like:

. . $\begin{array}{cccc} 2w + 3z &=& 6 & [1] \\<br /> 2x + 3z &=& 8 & [2] \\ y + 3z &=& 7 & [3] \end{array}$

I'm guessing my solution is going to be a general solution with a free parameter?

You are right!

$\begin{array}{ccccccc}\text{Solve [1] for }w: & w &=& \dfrac{6-3z}{2} \\ \\[-3mm]<br /> \text{Solve [2] for }x: & x &=& \dfrac{8-3z}{2} \\ \\[-3mm] \text{Solve [3] for }y: & y &=& 7 - 3z \\ \\[-2mm]<br /> \text{and we have:} & z&=& z \end{array}$

On the right, replace $z$ with a parameter $t.$

And we have: . $\begin{Bmatrix}w &=& \dfrac{6-3t}{2} \\ \\[-3mm]x &=& \dfrac{8-3t}{2} \\ \\[-2mm] y &=& 7-3t \\ \\ z &=& t \end{Bmatrix}$

**ZTM1989** · January 1st 2010, 08:06 AM

Thanks a lot.

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