Can you see that each term has been multiplied by ?

That means that you can take out as a common factor.

So .

Can you see that each term has in it? (note that and )

So we can take out as a common factor.

.

Can you see anything that goes into every term in this expression? I can't...

The best you could hope for in this case is to factorise groups of two...

.

We still don't get any common factors though...

This is a quadratic equation of the form .

We can factorise the quadratic by finding two numbers that multiply to be and add to be .

and .

What numbers multiply to be and add to be ? Surely the two numbers must be and .

Watch what happens when I break up the middle term...

.

If we factorise by groups of two, we can find a common factor...

Can you see that is a common factor?

.

Now we have two "things" multiplying to become . This means at least one of those "things" had to be .

So or .

Can you tell me what has to be?