# Thread: help with the powers on my first post

1. ## help with the powers on my first post

Reduce to the lowest power?

$\displaystyle /sqrt^6/frac{3}-{8}/frac/frac{1}-{4}$

2. Originally Posted by gillyman
Reduce to the lowest power?

$\displaystyle /sqrt^6/frac{3}-{8}/frac/frac{1}-{4}$
could you rewrite this using latex

3. Hope this is correct, its also my first time using LATEX
$\displaystyle (/sqrt)^{6}-/frac{3}{8}/frac{1}{4}$

4. Originally Posted by gillyman
Hope this is correct, its also my first time using LATEX
$\displaystyle (/sqrt)^{6}-/frac{3}{8}/frac{1}{4}$

$\displaystyle \sqrt{6}-\frac{\frac{3}{8}}{\frac{1}{4}}$

or

$\displaystyle \frac{\sqrt{6}}{\frac{3}{8}} - \frac{8}{\frac{1}{4}}$

sorry i know this is a pain but...

5. ## Its neither of these, Sorry

$\displaystyle \frac{(\sqrt)^6\frac{3}{8}}{\frac{1}{4}}$

I hope this is correct. I do need a crash course in LATEK.

6. Do you mean $\displaystyle \frac{\sqrt[6]{\frac{3}{8}}}{\frac{1}{4}}$?

That is $\displaystyle 4(3^{1/6})2^{1/2})= 2^{5/2}3^{1/6}$.