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Math Help - help with the powers on my first post

  1. #1
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    help with the powers on my first post

    Reduce to the lowest power?

    /sqrt^6/frac{3}-{8}/frac/frac{1}-{4}
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  2. #2
    Super Member bigwave's Avatar
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    Quote Originally Posted by gillyman View Post
    Reduce to the lowest power?

    /sqrt^6/frac{3}-{8}/frac/frac{1}-{4}
    could you rewrite this using latex
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  3. #3
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    Hope this is correct, its also my first time using LATEX
    (/sqrt)^{6}-/frac{3}{8}/frac{1}{4}
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  4. #4
    Super Member bigwave's Avatar
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    Cool

    Quote Originally Posted by gillyman View Post
    Hope this is correct, its also my first time using LATEX
    (/sqrt)^{6}-/frac{3}{8}/frac{1}{4}

    \sqrt{6}-\frac{\frac{3}{8}}{\frac{1}{4}}

    or

    \frac{\sqrt{6}}{\frac{3}{8}} - \frac{8}{\frac{1}{4}}

    sorry i know this is a pain but...
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  5. #5
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    Its neither of these, Sorry

    \frac{(\sqrt)^6\frac{3}{8}}{\frac{1}{4}}

    I hope this is correct. I do need a crash course in LATEK.
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  6. #6
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    Do you mean \frac{\sqrt[6]{\frac{3}{8}}}{\frac{1}{4}}?

    That is 4(3^{1/6})2^{1/2})= 2^{5/2}3^{1/6}.
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