Please solve the inequalities, (the results in set notation)
1) -2 (3+x)< 4x +4 < 8x
2) [2x - 4] < 10
3) 4 < -z - 4 < 11
1) Solve seperately: -6 - 2x < 4x + 4 and 4x + 4 < 8x:
-6 - 2x < 4x + 4 => -10 < 6x => 6x > -10 => x > -10/6.
4x + 4 < 8x => 4 < 4x => 4x > 4 => x > 1.
The answer will be the values of x common to both of these solutions.
Now try the others. If you need more help, please show your work and say where yuo get stuck.
The first answer is wrong - I haven't checked the others.