How do I solve this using any algebraic method?

3x-2y=10

5x+3y=15

2x-4y=-6

-x+2y=3

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- Dec 29th 2009, 03:16 PMVuongSolving Systems
How do I solve this using any algebraic method?

3x-2y=10

5x+3y=15

2x-4y=-6

-x+2y=3 - Dec 29th 2009, 03:31 PMintegral
solve for x on one equation and substitute it in the other

- Dec 29th 2009, 03:32 PMskeeter
- Dec 29th 2009, 03:33 PMBacterius

From the second equation you know that :

Thus

And so, .

Substituting back this result into the first equation gives :

Now substitute the value of found into any of the equations to retrieve .

Can you do it for the second system now ? :) - Dec 29th 2009, 03:36 PMpickslides
- Dec 29th 2009, 03:41 PMVuong
- Dec 29th 2009, 03:43 PMVuong
- Dec 29th 2009, 03:46 PMBacterius
- Dec 29th 2009, 03:46 PMpickslides
- Dec 29th 2009, 03:57 PMVuong
- Dec 29th 2009, 04:01 PMBacterius
That's not right, you should find something around :(

- Dec 29th 2009, 04:02 PMVuong
- Dec 29th 2009, 04:03 PMpickslides
- Dec 29th 2009, 04:06 PMVuong
- Dec 29th 2009, 04:08 PMBacterius