A review question I'm not sure how to answer, the question says to add or subtract whenever possible and to simplify the answer. $\displaystyle 3\sqrt{50}+4\sqrt{72} $
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You need to find square numbers inside the square root i.e 1,4,9,16,25,36,... to help simplify. $\displaystyle \sqrt{72} = \sqrt{2\times 36} = \sqrt{2}\times\sqrt{36} = \sqrt{2}\times 6 = 6\sqrt{2} $ Now do the same for the first term and finish.
$\displaystyle \sqrt{72} = 6\sqrt{2}$ and $\displaystyle \sqrt{50} = 5\sqrt{2}$ but what happens with the 3 and 4, I multiply them with the 6 and 5?
oh wait, i got the answer thank you so much
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