I am doing some review questions for University and don't recall how to answer a question like this (my answer should only have positive exponents) .... Thanks!
$\displaystyle
(x+3)^\frac{-1}{3}
$ $\displaystyle
-(x+3)^\frac{-4}{3}
$
I am doing some review questions for University and don't recall how to answer a question like this (my answer should only have positive exponents) .... Thanks!
$\displaystyle
(x+3)^\frac{-1}{3}
$ $\displaystyle
-(x+3)^\frac{-4}{3}
$
$\displaystyle (x+3)^{-\frac{1}{3}} - (x+3)^{-\frac{4}{3}}$
common factor for both terms is $\displaystyle (x+3)^{-\frac{4}{3}}$ ...
$\displaystyle (x+3)^{-\frac{4}{3}}[(x+3) - 1]$
$\displaystyle (x+3)^{-\frac{4}{3}}(x+2)$
$\displaystyle \frac{x+2}{(x+3)^{\frac{4}{3}}}
$