I am doing some review questions for University and don't recall how to answer a question like this (my answer should only have positive exponents) .... Thanks!

$\displaystyle

(x+3)^\frac{-1}{3}

$ $\displaystyle

-(x+3)^\frac{-4}{3}

$

Printable View

- Dec 29th 2009, 10:51 AMbearhugFactor and Simplify Algebraic Expression
I am doing some review questions for University and don't recall how to answer a question like this (my answer should only have positive exponents) .... Thanks!

$\displaystyle

(x+3)^\frac{-1}{3}

$ $\displaystyle

-(x+3)^\frac{-4}{3}

$ - Dec 29th 2009, 11:26 AMskeeter
$\displaystyle (x+3)^{-\frac{1}{3}} - (x+3)^{-\frac{4}{3}}$

common factor for both terms is $\displaystyle (x+3)^{-\frac{4}{3}}$ ...

$\displaystyle (x+3)^{-\frac{4}{3}}[(x+3) - 1]$

$\displaystyle (x+3)^{-\frac{4}{3}}(x+2)$

$\displaystyle \frac{x+2}{(x+3)^{\frac{4}{3}}}

$ - Dec 29th 2009, 12:30 PMRaoh