Hi

For the following equations

$\displaystyle Y=x+x^2-x^4 $

do the following steps are correct ?

$\displaystyle x+(x-x^2)(x+x^2)$

$\displaystyle x+x(1-x)(1+x)$

$\displaystyle x[1+1-x^2] $

$\displaystyle x[2-x^2]$

Thank you

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- Dec 26th 2009, 12:32 PMmetallica007Common Factor
Hi

For the following equations

$\displaystyle Y=x+x^2-x^4 $

do the following steps are correct ?

$\displaystyle x+(x-x^2)(x+x^2)$

$\displaystyle x+x(1-x)(1+x)$

$\displaystyle x[1+1-x^2] $

$\displaystyle x[2-x^2]$

Thank you - Dec 26th 2009, 01:34 PMRaoh
- Dec 26th 2009, 01:34 PMBacterius
No. The common factor is just $\displaystyle x$.

$\displaystyle Y=x+x^2-x^4$

$\displaystyle Y = x(1 + x - x^3)$

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When you are unsure about a result, just try with some numbers. With your result, what you are saying is that :

$\displaystyle x + x^2 - x^4 = x(2 - x^2)$

Take $\displaystyle x = 2$. Thus we get :

$\displaystyle 2 + 2^2 - 2^4 = 2(2 - 2^2)$

And therefore your results suggests that $\displaystyle -10 = -4$

But $\displaystyle -10 \neq -4$, thus your result is wrong. - Dec 26th 2009, 01:40 PMRaoh
- Dec 26th 2009, 02:39 PMmetallica007