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Math Help - Tricky one

  1. #1
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    Question Tricky one

    I'Am not sure if this can be answered. This is a real life question -

    Q) There are -
    1000 users in Group1
    200 users in Group2
    300 users in Group3

    Total 100 users are member of Both Group1 and Group2.
    Total 120 users are member of Both Group1 and Group3.

    Can it be concluded somehow how many users are both in Group2 and Group3??

    i dont think so, but i wanted to confirm from you experts.
    i know in Maximum worst case, we can have all 200 users of Group2 in both Group2 and Group3. But can an exact figure be calculated somehow??

    thanks.
    regards
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  2. #2
    MHF Contributor

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    Quote Originally Posted by aiwaxxx View Post
    I'Am not sure if this can be answered. This is a real life question -

    Q) There are -
    1000 users in Group1
    200 users in Group2
    300 users in Group3

    Total 100 users are member of Both Group1 and Group2.
    Total 120 users are member of Both Group1 and Group3.

    Can it be concluded somehow how many users are both in Group2 and Group3??

    i dont think so, but i wanted to confirm from you experts.
    i know in Maximum worst case, we can have all 200 users of Group2 in both Group2 and Group3. But can an exact figure be calculated somehow??

    thanks.
    regards
    I think you would need to know also how many users were in Groups 1, 2, and 3.
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  3. #3
    Senior Member
    Joined
    Feb 2008
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    383
    Quote Originally Posted by aiwaxxx View Post
    I'Am not sure if this can be answered. This is a real life question -

    Q) There are -
    1000 users in Group1
    200 users in Group2
    300 users in Group3

    Total 100 users are member of Both Group1 and Group2.
    Total 120 users are member of Both Group1 and Group3.

    Can it be concluded somehow how many users are both in Group2 and Group3??

    i dont think so, but i wanted to confirm from you experts.
    i know in Maximum worst case, we can have all 200 users of Group2 in both Group2 and Group3. But can an exact figure be calculated somehow??

    thanks.
    regards
    I think it depends on the relationship between the groups.

    If there is no relation, then 200 is the answer.
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  4. #4
    Junior Member
    Joined
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    Quote Originally Posted by aiwaxxx View Post
    I'Am not sure if this can be answered. This is a real life question -

    Q) There are -
    1000 users in Group1
    200 users in Group2
    300 users in Group3

    Total 100 users are member of Both Group1 and Group2.
    Total 120 users are member of Both Group1 and Group3.

    Can it be concluded somehow how many users are both in Group2 and Group3??

    i dont think so, but i wanted to confirm from you experts.
    i know in Maximum worst case, we can have all 200 users of Group2 in both Group2 and Group3. But can an exact figure be calculated somehow??

    thanks.
    regards
    I think you could also work it out if you knew the total number of users and the amount of users that are in all 3 groups.
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  5. #5
    Senior Member
    Joined
    Feb 2008
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    383
    Quote Originally Posted by aiwaxxx View Post
    I'Am not sure if this can be answered. This is a real life question -

    Q) There are -
    1000 users in Group1
    200 users in Group2
    300 users in Group3

    Total 100 users are member of Both Group1 and Group2.
    Total 120 users are member of Both Group1 and Group3.

    Can it be concluded somehow how many users are both in Group2 and Group3??

    i dont think so, but i wanted to confirm from you experts.
    i know in Maximum worst case, we can have all 200 users of Group2 in both Group2 and Group3. But can an exact figure be calculated somehow??

    thanks.
    regards
    could you like at this in this way? but it's most likely to be wrong:

    1000x+200y+0z=100
    1000x+0y+300z=120

    (200y+0z-100)/1000=x
    1000((200y+0z-100)/1000)+0y+300z=120
    200y-100+300z=120
    200y+300z=220

    but this is only based on the previous groups and it exceeds 200.
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