i have the equation

i opened up the modulus to get &

and the answer is supposed to be the inequality but ive no clue how to get to this. (Headbang)

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- December 23rd 2009, 02:23 AMrenlokmodulus equation
i have the equation

i opened up the modulus to get &

and the answer is supposed to be the inequality but ive no clue how to get to this. (Headbang) - December 23rd 2009, 02:28 AMred_dog
First of all, the right member must be nonnegative, as the left member is.

That means .

In this case the equation is which is true for all - December 23rd 2009, 02:49 AMHallsofIvy
**Provided**.

x- 1= 1- x reduces to 2x= 2 and then x= 1. Yes, that is satisifies x- 1= 0 and so is a valid solution.

Quote:

&

**Provided x- 1< 0**.

1-x= 1- x reduces to 0= 0 which is true for all x but we still have "x- 1< 0". Every x such that x- 1< 0, which says x< 1, is a solution. Putting that together with the first case says that all x such that is a solution.

Quote:

and the answer is supposed to be the inequality but ive no clue how to get to this. (Headbang)