Hello, sergeantjoker!

Find real numbersaandbsuch that

. . . _____ . . . ._ . . ._

. . √a + b .= .√a + √b

. . . . . . . . . . . . . . . . _____ . . . . . . _ . . . _

Square both sides: . (√a + b)² . = . (√a + √b)²

. . . . . . . . . . . . . . . . . . . . . . . .__

And we have: . a + b . = . a + 2√ab + b

. . . . . . . .__ . . . . . . . . .__

Then: . 2√ab .= .0 . → . √ab .= .0 . → . ab .= .0

Therefore: .either a = 0 or b = 0.