Can you help me find the equation of the line perpendicular to the line x=4, and passing through the point (4, 2)?

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- December 22nd 2009, 11:42 PMjay1equation of the line
Can you help me find the equation of the line perpendicular to the line x=4, and passing through the point (4, 2)?

- December 23rd 2009, 12:52 AMJoel
The equation x = 4 has a gradient that is undefined.

The perpendicular to this line would be 0, so

using the point slope form of an equation at the point (4,2)

y - y1 = m (x- x1)

y - 2 = 0 (x - 4)

y - 2 = 0

y = 2 is the equation of the line perpendicular to x = 4 at the point (4, 2) - December 23rd 2009, 01:14 AMBacterius
Joel, be more careful in the choice of your words :

Quote:

The perpendicular to this line would be 0, so

*The slope of the perpendicular to this line equals 0, so* - December 23rd 2009, 02:56 AMHallsofIvy
- December 23rd 2009, 02:57 AMHallsofIvy