Is it possible to solve for a and b in this equation?
a+3b+(3a-b)i = 6+6i
Just trying to help my son with his homework.
Thanks for any information
If you rearrange the first equation you can see that $\displaystyle a=6-3b$, so now you can plug this value of $\displaystyle a$ into the second equation, yielding $\displaystyle 3(6-3b)-b=6$
Solving this gives $\displaystyle b=\frac{6}{5}$
Now if you plug this value of $\displaystyle b$ into either of the first two equations you can find the value of $\displaystyle a$
For more info on how to solve simultaneous equations you should have a look here Practical Algebra Lessons