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Math Help - I'm stuck!

  1. #1
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    I'm stuck!

    I need help with this one: given g(x) = 5/x+3, find g(-3). Or is this undefined?
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  2. #2
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    Quote Originally Posted by jay1 View Post
    I need help with this one: given g(x) = 5/x+3, find g(-3). Or is this undefined?
    why undefined,just plug -3 and get g(-3).
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  3. #3
    A riddle wrapped in an enigma
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    Quote Originally Posted by jay1 View Post
    I need help with this one: given g(x) = 5/x+3, find g(-3). Or is this undefined?
    Hi jay1,

    g(x)=\frac{5}{x+3}

    g(-3)=\frac{5}{-3+3}

    g(-3)=\frac{5}{0}

    What do you think?
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  4. #4
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    Quote Originally Posted by masters View Post
    Hi jay1,

    g(x)=\frac{5}{x+3}

    g(-3)=\frac{5}{-3+3}

    g(-3)=\frac{5}{0}

    What do you think?
    i think he meant g(x)=\frac{5}{x}+3
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  5. #5
    A riddle wrapped in an enigma
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    Quote Originally Posted by Raoh View Post
    i think he meant g(x)=\frac{5}{x}+3
    You're right. That's the way he wrote it.

    But, I somehow think he meant it the way I responded. Could be wrong, though. We'll have to wait and hear from Jay to be sure.
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  6. #6
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    jay1, IF you mean \frac{5}{x+3}, then, yes, that function is undefined at x= -3.

    IF you mean \frac{5}{x}+ 3, then it is not. At x= -3, that is -\frac{5}{3}+ 3= \frac{4}{3}.
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  7. #7
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    That is the way I meant to write it; given that equation, find g(-3)
    Thanks!
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