1. ## I'm stuck!

I need help with this one: given g(x) = 5/x+3, find g(-3). Or is this undefined?

2. Originally Posted by jay1
I need help with this one: given g(x) = 5/x+3, find g(-3). Or is this undefined?
why undefined,just plug -3 and get g(-3).

3. Originally Posted by jay1
I need help with this one: given g(x) = 5/x+3, find g(-3). Or is this undefined?
Hi jay1,

$\displaystyle g(x)=\frac{5}{x+3}$

$\displaystyle g(-3)=\frac{5}{-3+3}$

$\displaystyle g(-3)=\frac{5}{0}$

What do you think?

4. Originally Posted by masters
Hi jay1,

$\displaystyle g(x)=\frac{5}{x+3}$

$\displaystyle g(-3)=\frac{5}{-3+3}$

$\displaystyle g(-3)=\frac{5}{0}$

What do you think?
i think he meant $\displaystyle g(x)=\frac{5}{x}+3$

5. Originally Posted by Raoh
i think he meant $\displaystyle g(x)=\frac{5}{x}+3$
You're right. That's the way he wrote it.

But, I somehow think he meant it the way I responded. Could be wrong, though. We'll have to wait and hear from Jay to be sure.

6. jay1, IF you mean $\displaystyle \frac{5}{x+3}$, then, yes, that function is undefined at x= -3.

IF you mean $\displaystyle \frac{5}{x}+ 3$, then it is not. At x= -3, that is $\displaystyle -\frac{5}{3}+ 3= \frac{4}{3}$.

7. That is the way I meant to write it; given that equation, find g(-3)
Thanks!