I need help with this one: given g(x) = 5/x+3, find g(-3). Or is this undefined?
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Originally Posted by jay1 I need help with this one: given g(x) = 5/x+3, find g(-3). Or is this undefined? why undefined,just plug -3 and get g(-3).
Originally Posted by jay1 I need help with this one: given g(x) = 5/x+3, find g(-3). Or is this undefined? Hi jay1, $\displaystyle g(x)=\frac{5}{x+3}$ $\displaystyle g(-3)=\frac{5}{-3+3}$ $\displaystyle g(-3)=\frac{5}{0}$ What do you think?
Originally Posted by masters Hi jay1, $\displaystyle g(x)=\frac{5}{x+3}$ $\displaystyle g(-3)=\frac{5}{-3+3}$ $\displaystyle g(-3)=\frac{5}{0}$ What do you think? i think he meant $\displaystyle g(x)=\frac{5}{x}+3$
Originally Posted by Raoh i think he meant $\displaystyle g(x)=\frac{5}{x}+3$ You're right. That's the way he wrote it. But, I somehow think he meant it the way I responded. Could be wrong, though. We'll have to wait and hear from Jay to be sure.
jay1, IF you mean $\displaystyle \frac{5}{x+3}$, then, yes, that function is undefined at x= -3. IF you mean $\displaystyle \frac{5}{x}+ 3$, then it is not. At x= -3, that is $\displaystyle -\frac{5}{3}+ 3= \frac{4}{3}$.
That is the way I meant to write it; given that equation, find g(-3) Thanks!
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