Squares, complete the square, complex numbers, quadratic formula, discriminant

**jscalalamoboy** · December 21st 2009, 03:59 PM

Test next week, need some help with my assignments.

First completing the square: $x^2-8x+32=0$
I've done it 4 different ways and I've deduced that it is either
$-4+8i, -4-8i$
$-4+4i, -4-4i$
$4+8i, 4-8i$
$4+4i, 4-4i$

Okay.. Second.. This needs to be written in standard form.
$\frac{8-7i}{3-4i}$

Third, and last for the moment. Solve the equation:
$-x^2+4=2x^2-5$

More to come once I get to them.

**Quacky** · December 21st 2009, 04:08 PM

Idk number 2, but here're my attempts at one and 3:

1)

$(x-4)^2-4^2+32=0$
$<br /> (x-4)^2=-16<br />$
$(x-4)= \sqrt{-16} = 4i$
$<br /> x= 4+4i, x=4-4i<br />$

3)
$-x^2+4=2x^2-5$
$4=3x^2-5$
$9=3x^2$
$3=x^2$
$x=\sqrt{3}$

**Krahl** · December 21st 2009, 07:39 PM

2)
standar form is x+iy.

try multiplying the numerator and denominator of that expression by the conjugate of the denominator. the conjugate of a+ib is a-ib.

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