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Math Help - Tricky Re-arrangment

  1. #1
    Junior Member
    Joined
    Nov 2009
    Posts
    58

    Tricky Re-arrangment

    Hi,

    Would anyone be able to talk me through/just start me off getting from this:
    <br /> <br />
\frac{2}{3}(3-x)^{\frac{3}{2}} - 6 \sqrt{3-x}<br /> <br />

    to this:

    <br />
-\frac{2}{3}\sqrt{3-x} (x+6)<br />


    Thank You
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  2. #2
    MHF Contributor
    Joined
    Sep 2008
    From
    West Malaysia
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    1,261
    Quote Originally Posted by aceband View Post
    Hi,

    Would anyone be able to talk me through/just start me off getting from this:
    <br /> <br />
\frac{2}{3}(3-x)^{\frac{3}{2}} - 6 \sqrt{3-x}<br /> <br />

    to this:

    <br />
-\frac{2}{3}\sqrt{3-x} (x+6)<br />


    Thank You
    HI

    \frac{2}{3}(3-x)^{\frac{1}{2}}\cdot (3-x)-6(3-x)^{\frac{1}{2}}

    (3-x)^{\frac{1}{2}}[\frac{2}{3}(3-x)-6]

    \sqrt{3-x}(-4-\frac{2}{3}x)

    \sqrt{3-x}\cdot -\frac{12+2x}{3}

     <br />
-\frac{2}{3}\sqrt{3-x} (x+6)<br />
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  3. #3
    Junior Member
    Joined
    Nov 2009
    Posts
    58
    Thank you mathaddict.

    My day long battle with this question is over.

    Thanks
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