Tricky Re-arrangment

**aceband** · December 18th 2009, 05:52 AM

Hi,

Would anyone be able to talk me through/just start me off getting from this:
$ \frac{2}{3}(3-x)^{\frac{3}{2}} - 6 \sqrt{3-x} $

to this:

$ -\frac{2}{3}\sqrt{3-x} (x+6) $

Thank You

**mathaddict** · December 18th 2009, 06:37 AM

Originally Posted by aceband

Hi,

Would anyone be able to talk me through/just start me off getting from this:
$ \frac{2}{3}(3-x)^{\frac{3}{2}} - 6 \sqrt{3-x} $

to this:

$ -\frac{2}{3}\sqrt{3-x} (x+6) $

Thank You

HI

$\frac{2}{3}(3-x)^{\frac{1}{2}}\cdot (3-x)-6(3-x)^{\frac{1}{2}}$

$(3-x)^{\frac{1}{2}}[\frac{2}{3}(3-x)-6]$

$\sqrt{3-x}(-4-\frac{2}{3}x)$

$\sqrt{3-x}\cdot -\frac{12+2x}{3}$

$ -\frac{2}{3}\sqrt{3-x} (x+6) $

**aceband** · December 18th 2009, 06:53 AM

Thank you mathaddict.

My day long battle with this question is over.

Thanks

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