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Math Help - solving equations?

  1. #1
    Junior Member
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    solving equations?





    how would I solve these?
    Last edited by deekay930; December 17th 2009 at 07:22 PM.
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  2. #2
    Super Member bigwave's Avatar
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    no see

    the first one you can cross multiply

    x\sqrt{23} = 8\sqrt{6}

    x=\frac{8\sqrt{6}}{\sqrt{23}}

    the second simlifies to

    \frac{x^2}{2}
    Last edited by bigwave; December 18th 2009 at 09:08 AM. Reason: image loaded
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  3. #3
    Senior Member I-Think's Avatar
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    Your equations aren't showing on firefox, IE nor Google Chrome. Resubmit them please.
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  4. #4
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    I fixed it.
    Last edited by deekay930; December 17th 2009 at 08:00 PM.
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  5. #5
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    [quote=bigwave;426920]the first one you can cross multiply

    x\sqrt{23} = 8\sqrt{6}

    x=\frac{8\sqrt{6}}{\sqrt{23}}

    okay.
    Last edited by deekay930; December 18th 2009 at 09:56 AM.
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  6. #6
    Senior Member I-Think's Avatar
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    \frac{\sqrt{3x^8}}{\sqrt{12x^2}}

    \sqrt{\frac{3x^8}{12x^2}}

    \sqrt{\frac{x^4}{4}}

    \frac{x^2}{2}

    Edit: bigwave, it's not \frac{x^3}{2}, it's \frac{x^2}{2}
    Last edited by I-Think; December 18th 2009 at 07:14 AM.
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