The question is--

A web developer is building a web page which has a length of 11 in and width of 7 in. The website has frames along its top and to its left showing the links of different websites and pictures. These frames take up to one third of the computer screen/the web page. X is the width of the the frame where the top and left frames intersect at the left corner of the page. What is the length of X?

2. Originally Posted by skboss
The question is--

A web developer is building a web page which has a length of 11 in and width of 7 in. The website has frames along its top and to its left showing the links of different websites and pictures. These frames take up to one third of the computer screen/the web page. X is the width of the the frame where the top and left frames intersect at the left corner of the page. What is the length of X?

1. I assume that these frames have the same width. I call it x.

2. Draw a sketch of the page.

3. Then

$(7-x)(11-x)=\underbrace{\frac23 \cdot \overbrace{(7 \cdot 11)}^{\text{complete page}}}_{\text{outside the frames}}$

4. Solve for x. Be careful: There are some constraints to be observed.