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Math Help - Convert the decimal number

  1. #1
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    Convert the decimal number

    82 to binary form

    231 to octal form

    589 to hexadecimal form


    Help please and ty!!
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  2. #2
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    Quote Originally Posted by Draft View Post
    82 to binary form

    231 to octal form

    589 to hexadecimal form


    Help please and ty!!
    Use the method I've described here: http://www.mathhelpforum.com/math-he...ctal-form.html

    I'm going to show you the last example so you can see that and how it works:

    589 : 16 = 36 >>>>>> R = 13 that is D as hex number

    36 : 16 = 2 >>>>>>> R = 4

    2 : 16 = 0 >>>>>>> R = 2

    Therefore 589_{dec} = 24D_{hex}
    Last edited by earboth; December 16th 2009 at 10:49 PM. Reason: fixed the typo
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  3. #3
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    probably a stupid question, but what is the R??
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  4. #4
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    Quote Originally Posted by Draft View Post
    probably a stupid question, but what is the R??
    R means remainder.

    For instance 589 = 36 \cdot 16 + 13 . So if you divide 589 by 16 you get:

    589 : 16 = \dfrac{36 \cdot 16}{16}+\dfrac{13}{16} = 36 \text{ with the remainder } R = 13
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  5. #5
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    wrong topic mb
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  6. #6
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    Quote Originally Posted by Draft View Post
    82 to binary form
    2 divides into 82 41 times with 0 remainder
    82= 2(41)

    2 divides into 41 20 times with remainder 1
    41= 2(20)+ 1 so 82= 2(2(20)+ 1)

    2 divids into 20 10 times with remainder 0
    20= 2(10) so 82= 2(2(2(10))+ 1)

    2 divides into 10 5 times with remainder 0
    10= 2(5) so 82= 2(2(2(2(5)))+ 1

    2 divides into 5 2 times with remainder 1
    5= 2(2)+ 1 so 82= 2(2(2(2(2(2)+1))))+ 1

    2 divides into 2 1 with remainder 0
    2= 2(1) so 82= 2(2(2(2(2(2(1)+ 1))))+ 1= [tex]1(2^6)+ 0(2^5)+ 1(2^4)+ 0(2^3)+ 0(2^2)+ 1(2)+ 0

    82 base 10 is 101001 base 2.

    231 to octal form

    589 to hexadecimal form


    Help please and ty!!
    Try those two yourself. In hexadecimal, use "A" for "10", "B" for "11", "C" for "12", "D" for "13", "E" for "14", and "F" for "15".
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