# Thread: Convert the decimal number

1. ## Convert the decimal number

82 to binary form

231 to octal form

2. Originally Posted by Draft
82 to binary form

231 to octal form

Use the method I've described here: http://www.mathhelpforum.com/math-he...ctal-form.html

I'm going to show you the last example so you can see that and how it works:

589 : 16 = 36 >>>>>> R = 13 that is D as hex number

36 : 16 = 2 >>>>>>> R = 4

2 : 16 = 0 >>>>>>> R = 2

Therefore $589_{dec} = 24D_{hex}$

3. probably a stupid question, but what is the R??

4. Originally Posted by Draft
probably a stupid question, but what is the R??
R means remainder.

For instance $589 = 36 \cdot 16 + 13$ . So if you divide 589 by 16 you get:

$589 : 16 = \dfrac{36 \cdot 16}{16}+\dfrac{13}{16} = 36 \text{ with the remainder } R = 13$

5. wrong topic mb

6. Originally Posted by Draft
82 to binary form
2 divides into 82 41 times with 0 remainder
82= 2(41)

2 divides into 41 20 times with remainder 1
41= 2(20)+ 1 so 82= 2(2(20)+ 1)

2 divids into 20 10 times with remainder 0
20= 2(10) so 82= 2(2(2(10))+ 1)

2 divides into 10 5 times with remainder 0
10= 2(5) so 82= 2(2(2(2(5)))+ 1

2 divides into 5 2 times with remainder 1
5= 2(2)+ 1 so 82= 2(2(2(2(2(2)+1))))+ 1

2 divides into 2 1 with remainder 0
2= 2(1) so 82= 2(2(2(2(2(2(1)+ 1))))+ 1= [tex]1(2^6)+ 0(2^5)+ 1(2^4)+ 0(2^3)+ 0(2^2)+ 1(2)+ 0

82 base 10 is 101001 base 2.

231 to octal form