82 to binary form

231 to octal form

589 to hexadecimal form

Help please and ty!!

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- Dec 16th 2009, 10:17 PMDraftConvert the decimal number
82 to binary form

231 to octal form

589 to hexadecimal form

Help please and ty!! - Dec 16th 2009, 10:32 PMearboth
Use the method I've described here: http://www.mathhelpforum.com/math-he...ctal-form.html

I'm going to show you the last example so you can see that and how it works:

589 : 16 = 36 >>>>>> R = 13 that is**D**as hex number

36 : 16 = 2 >>>>>>> R =**4**

2 : 16 = 0 >>>>>>> R =**2**

Therefore $\displaystyle 589_{dec} = 24D_{hex}$ - Dec 16th 2009, 10:34 PMDraft
probably a stupid question, but what is the R??

- Dec 16th 2009, 10:48 PMearboth
- Dec 16th 2009, 11:09 PMDraft
wrong topic mb

- Dec 17th 2009, 04:20 AMHallsofIvy
2 divides into 82 41 times with 0 remainder

82= 2(41)

2 divides into 41 20 times with remainder 1

41= 2(20)+ 1 so 82= 2(2(20)+ 1)

2 divids into 20 10 times with remainder 0

20= 2(10) so 82= 2(2(2(10))+ 1)

2 divides into 10 5 times with remainder 0

10= 2(5) so 82= 2(2(2(2(5)))+ 1

2 divides into 5 2 times with remainder 1

5= 2(2)+ 1 so 82= 2(2(2(2(2(2)+1))))+ 1

2 divides into 2 1 with remainder 0

2= 2(1) so 82= 2(2(2(2(2(2(1)+ 1))))+ 1= [tex]1(2^6)+ 0(2^5)+ 1(2^4)+ 0(2^3)+ 0(2^2)+ 1(2)+ 0

82 base 10 is 101001 base 2.

Quote:

231 to octal form

589 to hexadecimal form

Help please and ty!!