# Math Help - Octal form

1. ## Octal form

Convert the decimal (base ten) number 2695 to octal form (base eight)

2. Originally Posted by Draft
Convert the decimal (base ten) number 2695 to octal form (base eight)

Divide the number by 8 and write down the remainder:

2695 : 8 = 336 >>>> R = 7

336 : 8 = 42 >>>> R = 0

42 : 8 = 5 >>>> R = 2

5 : 8 = 0 >>>> R = 5

Therefore

$2695_{10} = 5207_8$

3. how do u get

336 >>>> R = 7

etc

4. Originally Posted by Draft
how do u get

336 >>>> R = 7

etc
Pardon?
Code:
  2695 : 8 = 336
-(24)
-----
29
-(24)
-----
55
-(48)
-----
7  <<<<<< this is the remainder

5. i'm sorry this is really confusing for me, where did you get the 24? and the 29? and then the 55 and 48?

6. He said in his first post: divide by 8.

8 divides into 2695 336 times with remainder 7.
So 2695= 8(336)+ 7

8 divides into 336 42 times with remainder 0.
So 336= 8(42) and 2695= 8(8(42))+ 7

8 divides into 42 5 times with remainder 2.
So 42= 8(5)+ 2 and 2695= 8(8(8(5)+ 2)+ 7= $8=5(8^3)+ 2(8^2)+ 0(8)+ 7$.

The octal form of $2695_{10}$ is $5207_8$.