It's hard to type this expression, the 5's 2's and -2 in red are exponents. Please help simplify: (2a5b2/4a5b-2) -4

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- Dec 16th 2009, 05:38 PMjay1Can you help simplify?
It's hard to type this expression, the 5's 2's and -2 in red are exponents. Please help simplify: (2a5b2/4a5b-2) -4

- Dec 16th 2009, 05:40 PMpickslides
- Dec 16th 2009, 05:41 PMbigwave
lets see you try the first step

- Dec 16th 2009, 05:43 PMpickslides
You should consider the following

$\displaystyle a^m\div a^n = a^{m-n}$ - Dec 16th 2009, 05:49 PMjay1
Yes pickslides, the above is the expression...tI'm having trouble sorting thru..thanks much

- Dec 16th 2009, 05:56 PMjay1
Is the answer b16/2?

- Dec 16th 2009, 05:57 PMpickslides
Here's one I prepared earlier

$\displaystyle \frac{3a^4b^3}{9a^4b^{-1}}-3$

first cancelling the coefficents 3 and 9 we get

$\displaystyle \frac{a^4b^3}{3a^4b^{-1}}-3$

$\displaystyle a^4 $ is similar to both top and bottom as they cancel completely

$\displaystyle \frac{b^3}{3b^{-1}}-3$

Now lets take care of the b terms with the rule $\displaystyle a^m\div a^n = a^{m-n}$

$\displaystyle \frac{b^{3-(-1)}}{3}-3$

finally

$\displaystyle \frac{b^4}{3}-3$

and making a common denominator of 3 in both terms gives

$\displaystyle \frac{b^4-9}{3}$

Now use this example to finish yours!