solve the equation for 2q+3/3 + 3q-4/6 = q-2/2
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Originally Posted by jay1 solve the equation for 2q+3/3 + 3q-4/6 = q-2/2 please use parentheses to make your post more clear to others ...
(2q+3)/3 + (3q-4)/6 = (q-2)/2
to "clear" the fractions, multiply every term by the LCM of 3, 6, and 2 ... which is 6.
2(2q+3) + (3q-4) = 3(q-2)
take it from here?
Multiply both sides by 6 to get rid of the fractions.
Distribute 2 into (2q + 3) and 3 into (q - 2).
Combine like terms.
Subtract 3q from both sides and subtract 2 from both sides to isolate q.
Divide by 4 on both sides.
I am confused.. can you help me find q? Thanks so much?