# Math Help - Help please!

1. ## Help please!

solve the equation for 2q+3/3 + 3q-4/6 = q-2/2

2. Originally Posted by jay1
solve the equation for 2q+3/3 + 3q-4/6 = q-2/2
please use parentheses to make your post more clear to others ...

(2q+3)/3 + (3q-4)/6 = (q-2)/2

to "clear" the fractions, multiply every term by the LCM of 3, 6, and 2 ... which is 6.

2(2q+3) + (3q-4) = 3(q-2)

take it from here?

3. $\frac{2q+3}{3} + \frac{3q-4}{6} = \frac{q-2}{2}$

Multiply both sides by 6 to get rid of the fractions.

$2(2q + 3) + 3q - 4 = 3(q - 2)$

Distribute 2 into (2q + 3) and 3 into (q - 2).

$4q + 6 + 3q - 4 = 3q - 6$

Combine like terms.

$7q + 2 = 3q - 6$

Subtract 3q from both sides and subtract 2 from both sides to isolate q.

$4q = -8$

Divide by 4 on both sides.

$q = -2$

4. I am confused.. can you help me find q? Thanks so much?