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Math Help - Help please!

  1. #1
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    Help please!

    solve the equation for 2q+3/3 + 3q-4/6 = q-2/2
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  2. #2
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    Quote Originally Posted by jay1 View Post
    solve the equation for 2q+3/3 + 3q-4/6 = q-2/2
    please use parentheses to make your post more clear to others ...

    (2q+3)/3 + (3q-4)/6 = (q-2)/2

    to "clear" the fractions, multiply every term by the LCM of 3, 6, and 2 ... which is 6.

    2(2q+3) + (3q-4) = 3(q-2)

    take it from here?
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  3. #3
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    \frac{2q+3}{3}  + \frac{3q-4}{6} = \frac{q-2}{2}

    Multiply both sides by 6 to get rid of the fractions.

    2(2q + 3) + 3q - 4 = 3(q - 2)

    Distribute 2 into (2q + 3) and 3 into (q - 2).

    4q + 6 + 3q - 4 = 3q - 6

    Combine like terms.

    7q + 2 = 3q - 6

    Subtract 3q from both sides and subtract 2 from both sides to isolate q.

    4q = -8

    Divide by 4 on both sides.

    q = -2
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  4. #4
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    I am confused.. can you help me find q? Thanks so much?
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