Log3x – log3 (x-5) = log3 A Express A in terms of x. Hence, solve the equation Log3 x – log3 (x-5) = 1 Thank you so much.
Last edited by Jhevon; Dec 24th 2009 at 11:09 AM. Reason: Restored deleted post
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every single 3 is a base, it just didn't show up.
Originally Posted by kayteee92 Log3x – log3 (x-5) = log3 A Express A in terms of x. Hence, solve the equation Log3 x – log3 (x-5) = 1 Thank you so much. Recall that $\displaystyle \log_a X - \log_a Y = \log_a \frac XY$ So that, $\displaystyle \log_3 x - \log_3 (x - 5) = \log_3 A$ $\displaystyle \Rightarrow \log_3 \frac x{x - 5} = \log_3 A$ Now what?
oh okay, so next i did A = x/x-5 and i crossed multiplied to get x = A(x-5) but for the next part of the problem, i replaced this for x and now i am stuck. Your help is much appreciated!
Originally Posted by kayteee92 oh okay, so next i did A = x/(x-5) stop there. that is A in terms of x. but for the next part of the problem, i replaced this for x and now i am stuck. Your help is much appreciated! for the second part, A = 1. so...?
thank you very much!
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