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Thread: Multiplying and Dividing Polynomials?

  1. #1
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    Multiplying and Dividing Polynomials?

    Simplifying?

    I got the answer $\displaystyle 36c^4b^6a^2$for the problem $\displaystyle (-2ab^5)(-6abc)(3c^3)$.Could you show me how you would solve these expressions?

    $\displaystyle (-3a^2b^2+7)(-6ab+2)$

    $\displaystyle (x+3)(2x^2+7x+1)$
    Last edited by deekay930; Dec 16th 2009 at 05:19 PM.
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  2. #2
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    To simplify the expression $\displaystyle (-3a^2b^2 + 7)(-6ab + 2)$, distribute both $\displaystyle -3a^2b^2$ and $\displaystyle 7$ into $\displaystyle (-6ab + 2)$. Then, add the result (because you were adding $\displaystyle -3a^2b^2$ and $\displaystyle 7$).

    $\displaystyle (-3a^2b^2 + 7)(-6ab + 2) = (-3a^2b^2)(-6ab + 2) + 7(-6ab + 2) = 18a^3b^3 - 6a^2b^2 - 42ab - 14$

    To simplify the expression $\displaystyle (x + 3)(2x^2 + 7x + 1)$, distribute both $\displaystyle x$ and $\displaystyle 3$ into $\displaystyle (2x^2 + 7x + 1)$. Then, add the result.

    $\displaystyle (x + 3)(2x^2 + 7x + 1) = x(2x^2 + 7x + 1) + 3(2x^2 + 7x + 1) = 2x^3 + 7x^2 + x + 6x^2 + 21x + 3$

    Combine like terms.

    $\displaystyle 2x^3 + 13x^2 + 22x + 3$
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  3. #3
    Senior Member Stroodle's Avatar
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    Hi there.

    There's also some good explanations on how to do these here: Practical Algebra Lessons

    *edit - Oh, and your first answer is correct
    Last edited by Stroodle; Dec 16th 2009 at 05:51 PM. Reason: Added comment
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  4. #4
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    Sorry, so the expression $\displaystyle 2x^2y^2 7xy^3$ would equal :
    $\displaystyle 14x^5y^3$
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