Multiplying and Dividing Polynomials?

**deekay930** · December 16th 2009, 04:11 PM

Simplifying?

I got the answer $36c^4b^6a^2$ for the problem $(-2ab^5)(-6abc)(3c^3)$ .Could you show me how you would solve these expressions?

$(-3a^2b^2+7)(-6ab+2)$

$(x+3)(2x^2+7x+1)$

**NOX Andrew** · December 16th 2009, 05:39 PM

To simplify the expression $(-3a^2b^2 + 7)(-6ab + 2)$ , distribute both $-3a^2b^2$ and $7$ into $(-6ab + 2)$ . Then, add the result (because you were adding $-3a^2b^2$ and $7$ ).

$(-3a^2b^2 + 7)(-6ab + 2) = (-3a^2b^2)(-6ab + 2) + 7(-6ab + 2) = 18a^3b^3 - 6a^2b^2 - 42ab - 14$

To simplify the expression $(x + 3)(2x^2 + 7x + 1)$ , distribute both $x$ and $3$ into $(2x^2 + 7x + 1)$ . Then, add the result.

$(x + 3)(2x^2 + 7x + 1) = x(2x^2 + 7x + 1) + 3(2x^2 + 7x + 1) = 2x^3 + 7x^2 + x + 6x^2 + 21x + 3$

Combine like terms.

$2x^3 + 13x^2 + 22x + 3$

**Stroodle** · December 16th 2009, 05:41 PM

Hi there.

There's also some good explanations on how to do these here: Practical Algebra Lessons

*edit - Oh, and your first answer is correct

**deekay930** · December 17th 2009, 11:12 AM

Sorry, so the expression $2x^2y^2 • 7xy^3$ would equal :
$14x^5y^3$

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