Simplifying?
I got the answer $\displaystyle 36c^4b^6a^2$for the problem $\displaystyle (-2ab^5)(-6abc)(3c^3)$.Could you show me how you would solve these expressions?
$\displaystyle (-3a^2b^2+7)(-6ab+2)$
$\displaystyle (x+3)(2x^2+7x+1)$
Simplifying?
I got the answer $\displaystyle 36c^4b^6a^2$for the problem $\displaystyle (-2ab^5)(-6abc)(3c^3)$.Could you show me how you would solve these expressions?
$\displaystyle (-3a^2b^2+7)(-6ab+2)$
$\displaystyle (x+3)(2x^2+7x+1)$
To simplify the expression $\displaystyle (-3a^2b^2 + 7)(-6ab + 2)$, distribute both $\displaystyle -3a^2b^2$ and $\displaystyle 7$ into $\displaystyle (-6ab + 2)$. Then, add the result (because you were adding $\displaystyle -3a^2b^2$ and $\displaystyle 7$).
$\displaystyle (-3a^2b^2 + 7)(-6ab + 2) = (-3a^2b^2)(-6ab + 2) + 7(-6ab + 2) = 18a^3b^3 - 6a^2b^2 - 42ab - 14$
To simplify the expression $\displaystyle (x + 3)(2x^2 + 7x + 1)$, distribute both $\displaystyle x$ and $\displaystyle 3$ into $\displaystyle (2x^2 + 7x + 1)$. Then, add the result.
$\displaystyle (x + 3)(2x^2 + 7x + 1) = x(2x^2 + 7x + 1) + 3(2x^2 + 7x + 1) = 2x^3 + 7x^2 + x + 6x^2 + 21x + 3$
Combine like terms.
$\displaystyle 2x^3 + 13x^2 + 22x + 3$
Hi there.
There's also some good explanations on how to do these here: Practical Algebra Lessons
*edit - Oh, and your first answer is correct