Simplifying?

I got the answer $\displaystyle 36c^4b^6a^2$for the problem $\displaystyle (-2ab^5)(-6abc)(3c^3)$.Could you show me how you would solve these expressions?

$\displaystyle (-3a^2b^2+7)(-6ab+2)$

$\displaystyle (x+3)(2x^2+7x+1)$

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- Dec 16th 2009, 04:11 PMdeekay930Multiplying and Dividing Polynomials?
Simplifying?

I got the answer $\displaystyle 36c^4b^6a^2$for the problem $\displaystyle (-2ab^5)(-6abc)(3c^3)$.Could you show me how you would solve these expressions?

$\displaystyle (-3a^2b^2+7)(-6ab+2)$

$\displaystyle (x+3)(2x^2+7x+1)$ - Dec 16th 2009, 05:39 PMNOX Andrew
To simplify the expression $\displaystyle (-3a^2b^2 + 7)(-6ab + 2)$, distribute both $\displaystyle -3a^2b^2$ and $\displaystyle 7$ into $\displaystyle (-6ab + 2)$. Then, add the result (because you were adding $\displaystyle -3a^2b^2$ and $\displaystyle 7$).

$\displaystyle (-3a^2b^2 + 7)(-6ab + 2) = (-3a^2b^2)(-6ab + 2) + 7(-6ab + 2) = 18a^3b^3 - 6a^2b^2 - 42ab - 14$

To simplify the expression $\displaystyle (x + 3)(2x^2 + 7x + 1)$, distribute both $\displaystyle x$ and $\displaystyle 3$ into $\displaystyle (2x^2 + 7x + 1)$. Then, add the result.

$\displaystyle (x + 3)(2x^2 + 7x + 1) = x(2x^2 + 7x + 1) + 3(2x^2 + 7x + 1) = 2x^3 + 7x^2 + x + 6x^2 + 21x + 3$

Combine like terms.

$\displaystyle 2x^3 + 13x^2 + 22x + 3$ - Dec 16th 2009, 05:41 PMStroodle
Hi there.

There's also some good explanations on how to do these here: Practical Algebra Lessons

*edit - Oh, and your first answer is correct :) - Dec 17th 2009, 11:12 AMdeekay930
Sorry, so the expression $\displaystyle 2x^2y^2 • 7xy^3$ would equal :

$\displaystyle 14x^5y^3$