Results 1 to 4 of 4

Math Help - Algebraic

  1. #1
    Member
    Joined
    Dec 2006
    Posts
    93
    Awards
    1

    Algebraic

    1. The sum of 5 and x divided by the difference of x and 8 and the result is 5.





    2. The sum of a number and 7 is equal to twice the difference of the number and 1.





    3. Six more than six times a number is 24.



    I can't seem to make any of these problems work out corectly.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by Patience View Post
    1. The sum of 5 and x divided by the difference of x and 8 and the result is 5.





    2. The sum of a number and 7 is equal to twice the difference of the number and 1.





    3. Six more than six times a number is 24.



    I can't seem to make any of these problems work out corectly.
    1. The sum of 5 and x divided by the difference of x and 8 and the result is 5.

    Remember "sum" means add and "difference" means subtract. So we have
    (x + 5)/(x - 8) = 5
    => x + 5 = 5(x - 8) ...........................I multiplied both sides by (x - 8)
    => x + 5 = 5x - 40 ............................I expanded the brackets
    => 40 + 5 = 5x - x ............................I put all the x's on one side and all the constants on the other
    => 45 = 4x
    => x = 45/4


    2. The sum of a number and 7 is equal to twice the difference of the number and 1.

    Note: sum = add, difference means subtract, twice means 2 times

    Let our number be x. We have:

    x + 7 = 2(x - 1)
    => x + 7 = 2x - 2
    => 7 + 2 = 2x - x
    => x = 9


    3. Six more than six times a number is 24.

    Let the number be x. We have

    6x + 6 = 24
    => 6x = 24 - 6
    => 6x = 18
    => x = 18/6
    => x = 3

    If there's anything you don't understand, say so
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Dec 2006
    Posts
    93
    Awards
    1

    Smile

    Thank you,

    The problem I have most with algebraic is translating it to an equation.
    You make it look so easy. The step by step you have showed me has help me so far.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by Patience View Post
    Thank you,

    The problem I have most with algebraic is translating it to an equation.
    You make it look so easy. The step by step you have showed me has help me so far.
    So you understand how to appraoch these problems now? How about you post another question and it's solution to let me see if you get it.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Algebraic q
    Posted in the Algebra Forum
    Replies: 1
    Last Post: December 13th 2009, 10:45 AM
  2. algebraic over K
    Posted in the Advanced Algebra Forum
    Replies: 5
    Last Post: October 14th 2009, 03:47 AM
  3. Algebraic
    Posted in the Advanced Algebra Forum
    Replies: 1
    Last Post: April 19th 2009, 10:20 AM
  4. Algebraic set
    Posted in the Advanced Algebra Forum
    Replies: 1
    Last Post: November 7th 2008, 07:28 PM
  5. Algebraic
    Posted in the Algebra Forum
    Replies: 3
    Last Post: March 1st 2007, 07:59 AM

Search Tags


/mathhelpforum @mathhelpforum