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Math Help - Newton Raphson, help please!

  1. #1
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    Exclamation Newton Raphson, help please!

    Hey, I've been stuck on a question for a while now, please help!

    Using the Newton Raphson method, which I'm not too clear on, I need to solve: x^3 + x -1 = 0, to 3 d.p
    and also
    cos x = x^2
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  2. #2
    Member kjchauhan's Avatar
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    Newton-Raphson :

    x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}

    Solve then by taking f(x)=x^3+x-1 and f'(x)=3x^2+1 and find the initial value x_2=\frac{x_1+x_0}{2}, where approx root lies between x_0 and x_1

    and then

    x_{2}=x_1-\frac{f(x_1)}{f'(x_1)}

    x_{3}=x_2-\frac{f(x_2)}{f'(x_2)}

    etc..
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