How do I find the area of an isosceles right triangle whose equal sides are 15cm each? Thanks, Ron
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Originally Posted by rn5a How do I find the area of an isosceles right triangle whose equal sides are 15cm each? Thanks, Ron Area = $\displaystyle \frac{1}{2}(base)(height)$ since base = height and let $\displaystyle s=15cm$ we have Area = $\displaystyle \frac{1}{2}s^2$
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