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How do i prove this? If x > 0, y > 0, prove that x + y ≥ 2√¯¯xy. Thanks.

Quote: Originally Posted by Detanon How do i prove this? If x > 0, y > 0, prove that x + y ≥ 2√¯¯xy. Thanks. $\displaystyle (a-b)^2\ge 0$ $\displaystyle a^2-2ab+b^2\ge 0$ Let $\displaystyle a=\sqrt{x}~\&~b=\sqrt{y}$